F(x-4)=x^2-3x+2

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Solution for F(x-4)=x^2-3x+2 equation: 



(F-4)=F^2-3F+2

We move all terms to the left:

(F-4)-(F^2-3F+2)=0

We get rid of parentheses

-F^2+F+3F-4-2=0

We add all the numbers together, and all the variables

-1F^2+4F-6=0

a = -1; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-1)·(-6)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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